In which of the following is the O-N-O bond a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the $O-N-O$ bond angle,we look at the hybridization and geometry of the molecules:$1$. $NO_2^+$: The nitrogen atom is $sp$-hybridized

Vedclass · Accepted Answer

$NO_2^+$

Vedclass · Answer

(B) To determine the $O-N-O$ bond angle,we look at the hybridization and geometry of the molecules:$1$. $NO_2^+$: The nitrogen atom is $sp$-hybridized with a linear geometry. The bond angle is $180^{\circ}$.$2$. $NO_2$: The nitrogen atom is $sp^2$-hybridized with one unpaired electron. The bond angle is approximately $134^{\circ}$.$3$. $NO_2^-$: The nitrogen atom is $sp^2$-hybridized with one lone pair. The bond angle is approximately $115^{\circ}$.$4$. $NO_3^-$: The nitrogen atom is $sp^2$-hybridized with no lone pairs,resulting in a trigonal planar geometry. The bond angle is $120^{\circ}$.Comparing these values,the $O-N-O$ bond angle is highest in $NO_2^+$.

In which of the following is the $O-N-O$ bond angle highest?

Similar Questions

What information does the $VSEPR$ theory provide about chemically bonded molecules,and what are its limitations?

Which of the following molecules has trigonal planar geometry?

The geometry of $ClO_3^-$ according to valence shell electron pair repulsion $(VSEPR)$ theory will be

The compound$(s)$ with $2$ lone pairs of electrons on the central atom is(are):
$(A)$ $BrF_5$
$(B)$ $ClF_3$
$(C)$ $XeF_4$
$(D)$ $SF_4$

Which of the following is $NOT$ tetrahedral in shape?

Vedclass Test Series

Exam Paper Generator

Online Exam Module